192=12t^2

Solution for 192=12t^2 equation:

192=12t^2

We move all terms to the left:

192-(12t^2)=0

a = -12; b = 0; c = +192;
Δ = b2-4ac
Δ = 02-4·(-12)·192
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9216}=96$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-96}{2*-12}=\frac{-96}{-24}
=+4
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+96}{2*-12}=\frac{96}{-24}
=-4
$